Base | Representation |
---|---|
bin | 1100101101001… |
… | …1011111000001 |
3 | 10201021200001102 |
4 | 3023103133001 |
5 | 102120420131 |
6 | 5142144145 |
7 | 1215000062 |
oct | 313233701 |
9 | 121250042 |
10 | 53295041 |
11 | 280a1398 |
12 | 15a22055 |
13 | b070137 |
14 | 7114569 |
15 | 4a2b1cb |
hex | 32d37c1 |
53295041 has 2 divisors, whose sum is σ = 53295042. Its totient is φ = 53295040.
The previous prime is 53295023. The next prime is 53295043. The reversal of 53295041 is 14059235.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53290000 + 5041 = 7300^2 + 71^2 .
It is a cyclic number.
It is not a de Polignac number, because 53295041 - 214 = 53278657 is a prime.
It is a super-2 number, since 2×532950412 = 5680722790383362, which contains 22 as substring.
Together with 53295043, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 53294995 and 53295013.
It is not a weakly prime, because it can be changed into another prime (53295043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26647520 + 26647521.
It is an arithmetic number, because the mean of its divisors is an integer number (26647521).
Almost surely, 253295041 is an apocalyptic number.
It is an amenable number.
53295041 is a deficient number, since it is larger than the sum of its proper divisors (1).
53295041 is an equidigital number, since it uses as much as digits as its factorization.
53295041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 29.
The square root of 53295041 is about 7300.3452658076. The cubic root of 53295041 is about 376.3243038205.
It can be divided in two parts, 5329 and 5041, that multiplied together give a square (26863489 = 51832).
The spelling of 53295041 in words is "fifty-three million, two hundred ninety-five thousand, forty-one".
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