Base | Representation |
---|---|
bin | 1001111011011001… |
… | …00000100001110001 |
3 | 111202110102100020121 |
4 | 10331230200201301 |
5 | 41403442420131 |
6 | 2240521210241 |
7 | 246040430626 |
oct | 47554404161 |
9 | 14673370217 |
10 | 5330045041 |
11 | 2295742802 |
12 | 1049030981 |
13 | 66c349009 |
14 | 387c5634d |
15 | 212dec911 |
hex | 13db20871 |
5330045041 has 2 divisors, whose sum is σ = 5330045042. Its totient is φ = 5330045040.
The previous prime is 5330045029. The next prime is 5330045051. The reversal of 5330045041 is 1405400335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5086685041 + 243360000 = 71321^2 + 15600^2 .
It is a cyclic number.
It is not a de Polignac number, because 5330045041 - 25 = 5330045009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5330044997 and 5330045015.
It is not a weakly prime, because it can be changed into another prime (5330045051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2665022520 + 2665022521.
It is an arithmetic number, because the mean of its divisors is an integer number (2665022521).
Almost surely, 25330045041 is an apocalyptic number.
It is an amenable number.
5330045041 is a deficient number, since it is larger than the sum of its proper divisors (1).
5330045041 is an equidigital number, since it uses as much as digits as its factorization.
5330045041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3600, while the sum is 25.
The square root of 5330045041 is about 73007.1574641829. The cubic root of 5330045041 is about 1746.8017821581.
Adding to 5330045041 its reverse (1405400335), we get a palindrome (6735445376).
The spelling of 5330045041 in words is "five billion, three hundred thirty million, forty-five thousand, forty-one".
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