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533021405220134 = 2594517130552713
BaseRepresentation
bin111100100110001111011011…
…1100001000000110100100110
32120220021100102012020112020122
41321030132313201000310212
51024331010314214021014
65125350353024401542
7220162345213231625
oct17114366741006446
92526240365215218
10533021405220134
11144923121453276
124b9471521762b2
1319b5591a19625c
14958a5334956bc
15419519b20d58e
hex1e4c7b7840d26

533021405220134 has 8 divisors (see below), whose sum is σ = 813083499488520. Its totient is φ = 261993572057296.

The previous prime is 533021405220127. The next prime is 533021405220163. The reversal of 533021405220134 is 431022504120335.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×5330214052201342 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 533021405220094 and 533021405220103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2258565276239 + ... + 2258565276474.

It is an arithmetic number, because the mean of its divisors is an integer number (101635437436065).

Almost surely, 2533021405220134 is an apocalyptic number.

533021405220134 is a deficient number, since it is larger than the sum of its proper divisors (280062094268386).

533021405220134 is a wasteful number, since it uses less digits than its factorization.

533021405220134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4517130552774.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 533021405220134 its reverse (431022504120335), we get a palindrome (964043909340469).

The spelling of 533021405220134 in words is "five hundred thirty-three trillion, twenty-one billion, four hundred five million, two hundred twenty thousand, one hundred thirty-four".

Divisors: 1 2 59 118 4517130552713 9034261105426 266510702610067 533021405220134