Base | Representation |
---|---|
bin | 111100100110001111011011… |
… | …1100001000000110100100110 |
3 | 2120220021100102012020112020122 |
4 | 1321030132313201000310212 |
5 | 1024331010314214021014 |
6 | 5125350353024401542 |
7 | 220162345213231625 |
oct | 17114366741006446 |
9 | 2526240365215218 |
10 | 533021405220134 |
11 | 144923121453276 |
12 | 4b9471521762b2 |
13 | 19b5591a19625c |
14 | 958a5334956bc |
15 | 419519b20d58e |
hex | 1e4c7b7840d26 |
533021405220134 has 8 divisors (see below), whose sum is σ = 813083499488520. Its totient is φ = 261993572057296.
The previous prime is 533021405220127. The next prime is 533021405220163. The reversal of 533021405220134 is 431022504120335.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×5330214052201342 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 533021405220094 and 533021405220103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2258565276239 + ... + 2258565276474.
It is an arithmetic number, because the mean of its divisors is an integer number (101635437436065).
Almost surely, 2533021405220134 is an apocalyptic number.
533021405220134 is a deficient number, since it is larger than the sum of its proper divisors (280062094268386).
533021405220134 is a wasteful number, since it uses less digits than its factorization.
533021405220134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4517130552774.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 533021405220134 its reverse (431022504120335), we get a palindrome (964043909340469).
The spelling of 533021405220134 in words is "five hundred thirty-three trillion, twenty-one billion, four hundred five million, two hundred twenty thousand, one hundred thirty-four".
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