Base | Representation |
---|---|
bin | 111100100110010100000000… |
… | …1010110111100100110111100 |
3 | 2120220022021210011212210200010 |
4 | 1321030220001112330212330 |
5 | 1024331140431402430022 |
6 | 5125355100214103220 |
7 | 220163143611600204 |
oct | 17114500126744674 |
9 | 2526267704783603 |
10 | 533031234030012 |
11 | 144927305572643 |
12 | 4b94903594ab10 |
13 | 19b568255757a3 |
14 | 958abc69b5404 |
15 | 419557405350c |
hex | 1e4ca015bc9bc |
533031234030012 has 48 divisors (see below), whose sum is σ = 1283870103821312. Its totient is φ = 171944229824640.
The previous prime is 533031234030011. The next prime is 533031234030017. The reversal of 533031234030012 is 210030432130335.
It is a super-3 number, since 3×5330312340300123 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (533031234030011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43210443 + ... + 54159069.
Almost surely, 2533031234030012 is an apocalyptic number.
It is an amenable number.
533031234030012 is an abundant number, since it is smaller than the sum of its proper divisors (750838869791300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
533031234030012 is a wasteful number, since it uses less digits than its factorization.
533031234030012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11079538 (or 11079536 counting only the distinct ones).
The product of its (nonzero) digits is 19440, while the sum is 30.
Adding to 533031234030012 its reverse (210030432130335), we get a palindrome (743061666160347).
The spelling of 533031234030012 in words is "five hundred thirty-three trillion, thirty-one billion, two hundred thirty-four million, thirty thousand, twelve".
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