Base | Representation |
---|---|
bin | 100110110010001011001… |
… | …1110000100000111100001 |
3 | 200212120202221002011020002 |
4 | 1031210112132010013201 |
5 | 1144313210414104043 |
6 | 15200433312025345 |
7 | 1060053026161556 |
oct | 115442636040741 |
9 | 20776687064202 |
10 | 5330431394273 |
11 | 1775694615787 |
12 | 7210a6832255 |
13 | 2c887176c03b |
14 | 145dcc34aa2d |
15 | 939cb81ebb8 |
hex | 4d9167841e1 |
5330431394273 has 2 divisors, whose sum is σ = 5330431394274. Its totient is φ = 5330431394272.
The previous prime is 5330431394263. The next prime is 5330431394377. The reversal of 5330431394273 is 3724931340335.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3954239629729 + 1376191764544 = 1988527^2 + 1173112^2 .
It is a cyclic number.
It is not a de Polignac number, because 5330431394273 - 224 = 5330414617057 is a prime.
It is not a weakly prime, because it can be changed into another prime (5330431394263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2665215697136 + 2665215697137.
It is an arithmetic number, because the mean of its divisors is an integer number (2665215697137).
Almost surely, 25330431394273 is an apocalyptic number.
It is an amenable number.
5330431394273 is a deficient number, since it is larger than the sum of its proper divisors (1).
5330431394273 is an equidigital number, since it uses as much as digits as its factorization.
5330431394273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2449440, while the sum is 47.
The spelling of 5330431394273 in words is "five trillion, three hundred thirty billion, four hundred thirty-one million, three hundred ninety-four thousand, two hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •