Base | Representation |
---|---|
bin | 1111100000111000100… |
… | …01111001110011011001 |
3 | 1212221220012100222200222 |
4 | 13300130101321303121 |
5 | 32213141400244321 |
6 | 1044514024005425 |
7 | 53340325432502 |
oct | 7603421716331 |
9 | 1787805328628 |
10 | 533050399961 |
11 | 19607a066132 |
12 | 87385600875 |
13 | 3b360492861 |
14 | 1bb2a833ba9 |
15 | dcec4593ab |
hex | 7c1c479cd9 |
533050399961 has 2 divisors, whose sum is σ = 533050399962. Its totient is φ = 533050399960.
The previous prime is 533050399913. The next prime is 533050400059. The reversal of 533050399961 is 169993050335.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 532380366736 + 670033225 = 729644^2 + 25885^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-533050399961 is a prime.
It is not a weakly prime, because it can be changed into another prime (533050399901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266525199980 + 266525199981.
It is an arithmetic number, because the mean of its divisors is an integer number (266525199981).
Almost surely, 2533050399961 is an apocalyptic number.
It is an amenable number.
533050399961 is a deficient number, since it is larger than the sum of its proper divisors (1).
533050399961 is an equidigital number, since it uses as much as digits as its factorization.
533050399961 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2952450, while the sum is 53.
The spelling of 533050399961 in words is "five hundred thirty-three billion, fifty million, three hundred ninety-nine thousand, nine hundred sixty-one".
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