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533100131 is a prime number
BaseRepresentation
bin11111110001100…
…111011001100011
31101011010021220022
4133301213121203
52042433201011
6124522104055
716132163534
oct3761473143
91334107808
10533100131
11253a15023
1212a64b02b
13865a4185
1450b3068b
1531c058db
hex1fc67663

533100131 has 2 divisors, whose sum is σ = 533100132. Its totient is φ = 533100130.

The previous prime is 533100103. The next prime is 533100133. The reversal of 533100131 is 131001335.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-533100131 is a prime.

It is a super-2 number, since 2×5331001312 = 568391499344434322, which contains 22 as substring.

Together with 533100133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (533100133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266550065 + 266550066.

It is an arithmetic number, because the mean of its divisors is an integer number (266550066).

Almost surely, 2533100131 is an apocalyptic number.

533100131 is a deficient number, since it is larger than the sum of its proper divisors (1).

533100131 is an equidigital number, since it uses as much as digits as its factorization.

533100131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 17.

The square root of 533100131 is about 23088.9612369201. The cubic root of 533100131 is about 810.8420502032.

Adding to 533100131 its reverse (131001335), we get a palindrome (664101466).

The spelling of 533100131 in words is "five hundred thirty-three million, one hundred thousand, one hundred thirty-one".