53311403533 has 2 divisors, whose sum is σ = 53311403534. Its totient is φ = 53311403532.

The previous prime is 53311403513. The next prime is 53311403539. The reversal of 53311403533 is 33530411335.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48711579849 + 4599823684 = 220707^2 + 67822^2 .

It is a cyclic number.

It is not a de Polignac number, because 53311403533 - 2⁵ = 53311403501 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53311403495 and 53311403504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53311403539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26655701766 + 26655701767.

It is an arithmetic number, because the mean of its divisors is an integer number (26655701767).

Almost surely, 2^53311403533 is an apocalyptic number.

It is an amenable number.

53311403533 is a deficient number, since it is larger than the sum of its proper divisors (1).

53311403533 is an equidigital number, since it uses as much as digits as its factorization.

53311403533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24300, while the sum is 31.

Adding to 53311403533 its reverse (33530411335), we get a palindrome (86841814868).

The spelling of 53311403533 in words is "fifty-three billion, three hundred eleven million, four hundred three thousand, five hundred thirty-three".