Base | Representation |
---|---|
bin | 110001101001100110… |
… | …111001010010000111 |
3 | 12002121100211022000010 |
4 | 301221212321102013 |
5 | 1333140210130320 |
6 | 40254012321303 |
7 | 3565051343130 |
oct | 615146712207 |
9 | 162540738003 |
10 | 53311411335 |
11 | 206779a1436 |
12 | a3b9a73233 |
13 | 5047b19110 |
14 | 281a43ac87 |
15 | 15c044dae0 |
hex | c699b9487 |
53311411335 has 64 divisors (see below), whose sum is σ = 107819937792. Its totient is φ = 21888216576.
The previous prime is 53311411333. The next prime is 53311411429.
53311411335 is nontrivially palindromic in base 10.
53311411335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53311411335 - 21 = 53311411333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53311411333) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 477279 + ... + 578288.
It is an arithmetic number, because the mean of its divisors is an integer number (1684686528).
Almost surely, 253311411335 is an apocalyptic number.
53311411335 is an abundant number, since it is smaller than the sum of its proper divisors (54508526457).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53311411335 is a wasteful number, since it uses less digits than its factorization.
53311411335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1055632.
The product of its digits is 8100, while the sum is 30.
The spelling of 53311411335 in words is "fifty-three billion, three hundred eleven million, four hundred eleven thousand, three hundred thirty-five".
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