Base | Representation |
---|---|
bin | 100110110010101001000… |
… | …0101100100010000110101 |
3 | 200212200100122011010210222 |
4 | 1031211102011210100311 |
5 | 1144322232442332201 |
6 | 15201120442024125 |
7 | 1060116562631654 |
oct | 115452205442065 |
9 | 20780318133728 |
10 | 5331431605301 |
11 | 177605817306a |
12 | 7213257a8045 |
13 | 2c89a0a51299 |
14 | 14608511119b |
15 | 93a3954391b |
hex | 4d952164435 |
5331431605301 has 2 divisors, whose sum is σ = 5331431605302. Its totient is φ = 5331431605300.
The previous prime is 5331431605249. The next prime is 5331431605309. The reversal of 5331431605301 is 1035061341335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3820953735076 + 1510477870225 = 1954726^2 + 1229015^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5331431605301 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5331431605309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2665715802650 + 2665715802651.
It is an arithmetic number, because the mean of its divisors is an integer number (2665715802651).
Almost surely, 25331431605301 is an apocalyptic number.
It is an amenable number.
5331431605301 is a deficient number, since it is larger than the sum of its proper divisors (1).
5331431605301 is an equidigital number, since it uses as much as digits as its factorization.
5331431605301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 35.
Adding to 5331431605301 its reverse (1035061341335), we get a palindrome (6366492946636).
The spelling of 5331431605301 in words is "five trillion, three hundred thirty-one billion, four hundred thirty-one million, six hundred five thousand, three hundred one".
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