Base | Representation |
---|---|
bin | 11000001111110110010101… |
… | …01110001010101010000001 |
3 | 20222210110010212222110201021 |
4 | 30013323022232022222001 |
5 | 23442103131012044244 |
6 | 305223215310305441 |
7 | 14142216121201645 |
oct | 1407731256125201 |
9 | 228713125873637 |
10 | 53321125112449 |
11 | 15a983a9057787 |
12 | 5b91ba8ab8281 |
13 | 239a2118904cc |
14 | d24a83122c25 |
15 | 627011475284 |
hex | 307ecab8aa81 |
53321125112449 has 2 divisors, whose sum is σ = 53321125112450. Its totient is φ = 53321125112448.
The previous prime is 53321125112447. The next prime is 53321125112557. The reversal of 53321125112449 is 94421152112335.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44166458266225 + 9154666846224 = 6645785^2 + 3025668^2 .
It is a cyclic number.
It is not a de Polignac number, because 53321125112449 - 21 = 53321125112447 is a prime.
Together with 53321125112447, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (53321125112447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26660562556224 + 26660562556225.
It is an arithmetic number, because the mean of its divisors is an integer number (26660562556225).
Almost surely, 253321125112449 is an apocalyptic number.
It is an amenable number.
53321125112449 is a deficient number, since it is larger than the sum of its proper divisors (1).
53321125112449 is an equidigital number, since it uses as much as digits as its factorization.
53321125112449 is an evil number, because the sum of its binary digits is even.
The product of its digits is 259200, while the sum is 43.
The spelling of 53321125112449 in words is "fifty-three trillion, three hundred twenty-one billion, one hundred twenty-five million, one hundred twelve thousand, four hundred forty-nine".
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