Base | Representation |
---|---|
bin | 11000001111111100011111… |
… | …01101110110010000111001 |
3 | 20222210202200012222021211121 |
4 | 30013332033231312100321 |
5 | 23442131413103443343 |
6 | 305224523252425241 |
7 | 14142364042365112 |
oct | 1407761755662071 |
9 | 228722605867747 |
10 | 53324430140473 |
11 | 15a998447161a8 |
12 | 5b9276b918221 |
13 | 239a61a5132ab |
14 | d24cb804b209 |
15 | 6271566bcaed |
hex | 307f8fb76439 |
53324430140473 has 2 divisors, whose sum is σ = 53324430140474. Its totient is φ = 53324430140472.
The previous prime is 53324430140447. The next prime is 53324430140479. The reversal of 53324430140473 is 37404103442335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48659162774544 + 4665267365929 = 6975612^2 + 2159923^2 .
It is a cyclic number.
It is not a de Polignac number, because 53324430140473 - 241 = 51125406884921 is a prime.
It is not a weakly prime, because it can be changed into another prime (53324430140479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26662215070236 + 26662215070237.
It is an arithmetic number, because the mean of its divisors is an integer number (26662215070237).
Almost surely, 253324430140473 is an apocalyptic number.
It is an amenable number.
53324430140473 is a deficient number, since it is larger than the sum of its proper divisors (1).
53324430140473 is an equidigital number, since it uses as much as digits as its factorization.
53324430140473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1451520, while the sum is 43.
The spelling of 53324430140473 in words is "fifty-three trillion, three hundred twenty-four billion, four hundred thirty million, one hundred forty thousand, four hundred seventy-three".
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