Base | Representation |
---|---|
bin | 11000001111111100011111… |
… | …01101110110010000011111 |
3 | 20222210202200012222021210122 |
4 | 30013332033231312100133 |
5 | 23442131413103443242 |
6 | 305224523252425155 |
7 | 14142364042365044 |
oct | 1407761755662037 |
9 | 228722605867718 |
10 | 53324430140447 |
11 | 15a99844716184 |
12 | 5b9276b9181bb |
13 | 239a61a51328b |
14 | d24cb804b1cb |
15 | 6271566bcad2 |
hex | 307f8fb7641f |
53324430140447 has 2 divisors, whose sum is σ = 53324430140448. Its totient is φ = 53324430140446.
The previous prime is 53324430140381. The next prime is 53324430140473. The reversal of 53324430140447 is 74404103442335.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53324430140447 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53324430140398 and 53324430140407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53324430146447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26662215070223 + 26662215070224.
It is an arithmetic number, because the mean of its divisors is an integer number (26662215070224).
Almost surely, 253324430140447 is an apocalyptic number.
53324430140447 is a deficient number, since it is larger than the sum of its proper divisors (1).
53324430140447 is an equidigital number, since it uses as much as digits as its factorization.
53324430140447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1935360, while the sum is 44.
The spelling of 53324430140447 in words is "fifty-three trillion, three hundred twenty-four billion, four hundred thirty million, one hundred forty thousand, four hundred forty-seven".
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