Base | Representation |
---|---|
bin | 1111100001010111101… |
… | …11111111000100011010 |
3 | 1212222120102200202001210 |
4 | 13300223313333010122 |
5 | 32214210340304432 |
6 | 1045000011523550 |
7 | 53346653361201 |
oct | 7605367770432 |
9 | 1788512622053 |
10 | 533312041242 |
11 | 1961a38200a2 |
12 | 874391595b6 |
13 | 3b3a274cb96 |
14 | 1bb534a0238 |
15 | dd153dc8cc |
hex | 7c2bdff11a |
533312041242 has 64 divisors (see below), whose sum is σ = 1140790210560. Its totient is φ = 165800342400.
The previous prime is 533312041237. The next prime is 533312041247. The reversal of 533312041242 is 242140213335.
It is an interprime number because it is at equal distance from previous prime (533312041237) and next prime (533312041247).
It is a super-3 number, since 3×5333120412423 (a number of 36 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (533312041247) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10334059 + ... + 10385537.
It is an arithmetic number, because the mean of its divisors is an integer number (17824847040).
Almost surely, 2533312041242 is an apocalyptic number.
533312041242 is an abundant number, since it is smaller than the sum of its proper divisors (607478169318).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
533312041242 is a wasteful number, since it uses less digits than its factorization.
533312041242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53379.
The product of its (nonzero) digits is 17280, while the sum is 30.
Adding to 533312041242 its reverse (242140213335), we get a palindrome (775452254577).
The spelling of 533312041242 in words is "five hundred thirty-three billion, three hundred twelve million, forty-one thousand, two hundred forty-two".
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