Base | Representation |
---|---|
bin | 100110110100000001110… |
… | …0111101110000000001001 |
3 | 200212222001012202122011021 |
4 | 1031220003213232000021 |
5 | 1144344332443002241 |
6 | 15202332202032441 |
7 | 1060253440632544 |
oct | 115500347560011 |
9 | 20788035678137 |
10 | 5334410125321 |
11 | 17773464a2262 |
12 | 721a171a8721 |
13 | 2c9056b54874 |
14 | 14628892585b |
15 | 93b60c930d1 |
hex | 4da039ee009 |
5334410125321 has 2 divisors, whose sum is σ = 5334410125322. Its totient is φ = 5334410125320.
The previous prime is 5334410125241. The next prime is 5334410125427. The reversal of 5334410125321 is 1235210144335.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2688078295296 + 2646331830025 = 1639536^2 + 1626755^2 .
It is a cyclic number.
It is not a de Polignac number, because 5334410125321 - 219 = 5334409601033 is a prime.
It is not a weakly prime, because it can be changed into another prime (5334410120321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667205062660 + 2667205062661.
It is an arithmetic number, because the mean of its divisors is an integer number (2667205062661).
Almost surely, 25334410125321 is an apocalyptic number.
It is an amenable number.
5334410125321 is a deficient number, since it is larger than the sum of its proper divisors (1).
5334410125321 is an equidigital number, since it uses as much as digits as its factorization.
5334410125321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 5334410125321 its reverse (1235210144335), we get a palindrome (6569620269656).
The spelling of 5334410125321 in words is "five trillion, three hundred thirty-four billion, four hundred ten million, one hundred twenty-five thousand, three hundred twenty-one".
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