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5334443113081 is a prime number
BaseRepresentation
bin100110110100000010110…
…0101100011101001111001
3200212222010111211120212011
41031220011211203221321
51144344414414104311
615202335341045521
71060254321214015
oct115500545435171
920788114746764
105334443113081
111777363083475
12721a262568a1
132c9060934754
1414628d071545
1593b63b0c321
hex4da05963a79

5334443113081 has 2 divisors, whose sum is σ = 5334443113082. Its totient is φ = 5334443113080.

The previous prime is 5334443113063. The next prime is 5334443113091. The reversal of 5334443113081 is 1803113444335.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5332940387856 + 1502725225 = 2309316^2 + 38765^2 .

It is a cyclic number.

It is not a de Polignac number, because 5334443113081 - 27 = 5334443112953 is a prime.

It is a super-2 number, since 2×53344431130812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5334443113091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667221556540 + 2667221556541.

It is an arithmetic number, because the mean of its divisors is an integer number (2667221556541).

Almost surely, 25334443113081 is an apocalyptic number.

It is an amenable number.

5334443113081 is a deficient number, since it is larger than the sum of its proper divisors (1).

5334443113081 is an equidigital number, since it uses as much as digits as its factorization.

5334443113081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 207360, while the sum is 40.

The spelling of 5334443113081 in words is "five trillion, three hundred thirty-four billion, four hundred forty-three million, one hundred thirteen thousand, eighty-one".