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5334443113117 is a prime number
BaseRepresentation
bin100110110100000010110…
…0101100011101010011101
3200212222010111211120220111
41031220011211203222131
51144344414414104432
615202335341050021
71060254321214066
oct115500545435235
920788114746814
105334443113117
1117773630834a8
12721a26256911
132c9060934781
1414628d07156d
1593b63b0c347
hex4da05963a9d

5334443113117 has 2 divisors, whose sum is σ = 5334443113118. Its totient is φ = 5334443113116.

The previous prime is 5334443113091. The next prime is 5334443113123. The reversal of 5334443113117 is 7113113444335.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4498920976356 + 835522136761 = 2121066^2 + 914069^2 .

It is a cyclic number.

It is not a de Polignac number, because 5334443113117 - 215 = 5334443080349 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5334443113117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5334443113177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667221556558 + 2667221556559.

It is an arithmetic number, because the mean of its divisors is an integer number (2667221556559).

Almost surely, 25334443113117 is an apocalyptic number.

It is an amenable number.

5334443113117 is a deficient number, since it is larger than the sum of its proper divisors (1).

5334443113117 is an equidigital number, since it uses as much as digits as its factorization.

5334443113117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 181440, while the sum is 40.

The spelling of 5334443113117 in words is "five trillion, three hundred thirty-four billion, four hundred forty-three million, one hundred thirteen thousand, one hundred seventeen".