Base | Representation |
---|---|
bin | 100110110100000101001… |
… | …1101111100101010100101 |
3 | 200212222100012221002200221 |
4 | 1031220022131330222211 |
5 | 1144400101400120303 |
6 | 15202351424204341 |
7 | 1060256334245251 |
oct | 115501235745245 |
9 | 20788305832627 |
10 | 5334525004453 |
11 | 17773a5326697 |
12 | 721a497696b1 |
13 | 2c90748a7998 |
14 | 146299cab261 |
15 | 93b6add64bd |
hex | 4da0a77caa5 |
5334525004453 has 2 divisors, whose sum is σ = 5334525004454. Its totient is φ = 5334525004452.
The previous prime is 5334525004421. The next prime is 5334525004463. The reversal of 5334525004453 is 3544005254335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3040081677889 + 2294443326564 = 1743583^2 + 1514742^2 .
It is a cyclic number.
It is not a de Polignac number, because 5334525004453 - 25 = 5334525004421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5334525004463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667262502226 + 2667262502227.
It is an arithmetic number, because the mean of its divisors is an integer number (2667262502227).
Almost surely, 25334525004453 is an apocalyptic number.
It is an amenable number.
5334525004453 is a deficient number, since it is larger than the sum of its proper divisors (1).
5334525004453 is an equidigital number, since it uses as much as digits as its factorization.
5334525004453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160000, while the sum is 43.
The spelling of 5334525004453 in words is "five trillion, three hundred thirty-four billion, five hundred twenty-five million, four thousand, four hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.110 sec. • engine limits •