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5334525004453 is a prime number
BaseRepresentation
bin100110110100000101001…
…1101111100101010100101
3200212222100012221002200221
41031220022131330222211
51144400101400120303
615202351424204341
71060256334245251
oct115501235745245
920788305832627
105334525004453
1117773a5326697
12721a497696b1
132c90748a7998
14146299cab261
1593b6add64bd
hex4da0a77caa5

5334525004453 has 2 divisors, whose sum is σ = 5334525004454. Its totient is φ = 5334525004452.

The previous prime is 5334525004421. The next prime is 5334525004463. The reversal of 5334525004453 is 3544005254335.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3040081677889 + 2294443326564 = 1743583^2 + 1514742^2 .

It is a cyclic number.

It is not a de Polignac number, because 5334525004453 - 25 = 5334525004421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5334525004463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667262502226 + 2667262502227.

It is an arithmetic number, because the mean of its divisors is an integer number (2667262502227).

Almost surely, 25334525004453 is an apocalyptic number.

It is an amenable number.

5334525004453 is a deficient number, since it is larger than the sum of its proper divisors (1).

5334525004453 is an equidigital number, since it uses as much as digits as its factorization.

5334525004453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160000, while the sum is 43.

The spelling of 5334525004453 in words is "five trillion, three hundred thirty-four billion, five hundred twenty-five million, four thousand, four hundred fifty-three".