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53345352976837 is a prime number
BaseRepresentation
bin11000010000100011011101…
…10100001000100111000101
320222212202200100222111120221
430020101232310020213011
523443002240330224322
6305242303345424341
714144034401512045
oct1410215664104705
9228782610874527
1053345352976837
1115aa77010548a9
125b9682a93b0b1
13239c5a314ba3c
14d25d00b15725
1562797d4769c7
hex30846ed089c5

53345352976837 has 2 divisors, whose sum is σ = 53345352976838. Its totient is φ = 53345352976836.

The previous prime is 53345352976819. The next prime is 53345352976849. The reversal of 53345352976837 is 73867925354335.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32322476901796 + 21022876075041 = 5685286^2 + 4585071^2 .

It is a cyclic number.

It is not a de Polignac number, because 53345352976837 - 219 = 53345352452549 is a prime.

It is a super-3 number, since 3×533453529768373 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53345352976037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26672676488418 + 26672676488419.

It is an arithmetic number, because the mean of its divisors is an integer number (26672676488419).

Almost surely, 253345352976837 is an apocalyptic number.

It is an amenable number.

53345352976837 is a deficient number, since it is larger than the sum of its proper divisors (1).

53345352976837 is an equidigital number, since it uses as much as digits as its factorization.

53345352976837 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1714608000, while the sum is 70.

The spelling of 53345352976837 in words is "fifty-three trillion, three hundred forty-five billion, three hundred fifty-two million, nine hundred seventy-six thousand, eight hundred thirty-seven".