Base | Representation |
---|---|
bin | 1111100001101000110… |
… | …11011000111111110101 |
3 | 1212222221102201020122111 |
4 | 13300310123120333311 |
5 | 32220004104241323 |
6 | 1045022135331021 |
7 | 53353345163431 |
oct | 7606433307765 |
9 | 1788842636574 |
10 | 533455540213 |
11 | 196267821a92 |
12 | 87479220a71 |
13 | 3b3c63b3a0b |
14 | 1bb685759c1 |
15 | dd22cd5c0d |
hex | 7c346d8ff5 |
533455540213 has 2 divisors, whose sum is σ = 533455540214. Its totient is φ = 533455540212.
The previous prime is 533455540207. The next prime is 533455540229. The reversal of 533455540213 is 312045554335.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 386875292049 + 146580248164 = 621993^2 + 382858^2 .
It is a cyclic number.
It is not a de Polignac number, because 533455540213 - 25 = 533455540181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (533455540613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266727770106 + 266727770107.
It is an arithmetic number, because the mean of its divisors is an integer number (266727770107).
Almost surely, 2533455540213 is an apocalyptic number.
It is an amenable number.
533455540213 is a deficient number, since it is larger than the sum of its proper divisors (1).
533455540213 is an equidigital number, since it uses as much as digits as its factorization.
533455540213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540000, while the sum is 40.
The spelling of 533455540213 in words is "five hundred thirty-three billion, four hundred fifty-five million, five hundred forty thousand, two hundred thirteen".
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