Base | Representation |
---|---|
bin | 100110110100011101010… |
… | …1000101011110000001011 |
3 | 200220001102112112212212102 |
4 | 1031220322220223300023 |
5 | 1144403230240001011 |
6 | 15203003533104015 |
7 | 1060315346203232 |
oct | 115507250536013 |
9 | 20801375485772 |
10 | 5335333125131 |
11 | 177777a503719 |
12 | 72203432800b |
13 | 2c9173141bb9 |
14 | 14633534bb19 |
15 | 93bb6d1473b |
hex | 4da3aa2bc0b |
5335333125131 has 2 divisors, whose sum is σ = 5335333125132. Its totient is φ = 5335333125130.
The previous prime is 5335333125047. The next prime is 5335333125137. The reversal of 5335333125131 is 1315213335335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5335333125131 - 242 = 937286614027 is a prime.
It is a super-3 number, since 3×53353331251313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (5335333125137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667666562565 + 2667666562566.
It is an arithmetic number, because the mean of its divisors is an integer number (2667666562566).
Almost surely, 25335333125131 is an apocalyptic number.
5335333125131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5335333125131 is an equidigital number, since it uses as much as digits as its factorization.
5335333125131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 182250, while the sum is 38.
The spelling of 5335333125131 in words is "five trillion, three hundred thirty-five billion, three hundred thirty-three million, one hundred twenty-five thousand, one hundred thirty-one".
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