Base | Representation |
---|---|
bin | 100110110100100000100… |
… | …1000011011111111000001 |
3 | 200220001201010122000100202 |
4 | 1031221001020123333001 |
5 | 1144403441140044244 |
6 | 15203022425054545 |
7 | 1060321141446431 |
oct | 115510110337701 |
9 | 20801633560322 |
10 | 5335442112449 |
11 | 1777825a83489 |
12 | 722064927455 |
13 | 2c918c8b1337 |
14 | 1463459dc2c1 |
15 | 93bc169204e |
hex | 4da4121bfc1 |
5335442112449 has 2 divisors, whose sum is σ = 5335442112450. Its totient is φ = 5335442112448.
The previous prime is 5335442112443. The next prime is 5335442112467. The reversal of 5335442112449 is 9442112445335.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5303809000000 + 31633112449 = 2303000^2 + 177857^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5335442112449 is a prime.
It is not a weakly prime, because it can be changed into another prime (5335442112443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667721056224 + 2667721056225.
It is an arithmetic number, because the mean of its divisors is an integer number (2667721056225).
Almost surely, 25335442112449 is an apocalyptic number.
It is an amenable number.
5335442112449 is a deficient number, since it is larger than the sum of its proper divisors (1).
5335442112449 is an equidigital number, since it uses as much as digits as its factorization.
5335442112449 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2073600, while the sum is 47.
The spelling of 5335442112449 in words is "five trillion, three hundred thirty-five billion, four hundred forty-two million, one hundred twelve thousand, four hundred forty-nine".
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