Base | Representation |
---|---|
bin | 100110110110101010000… |
… | …0110111011110000111011 |
3 | 200220111121122102222111122 |
4 | 1031231110012323300323 |
5 | 1144442413143441411 |
6 | 15205104305015455 |
7 | 1060543360263206 |
oct | 115552406736073 |
9 | 20814548388448 |
10 | 5340055452731 |
11 | 17797830a72aa |
12 | 722b3192458b |
13 | 2c97465bc69c |
14 | 1466625ac93d |
15 | 93d916bc9db |
hex | 4db541bbc3b |
5340055452731 has 2 divisors, whose sum is σ = 5340055452732. Its totient is φ = 5340055452730.
The previous prime is 5340055452701. The next prime is 5340055452733. The reversal of 5340055452731 is 1372545500435.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5340055452731 is a prime.
It is a super-2 number, since 2×53400554527312 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 5340055452733, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5340055452733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670027726365 + 2670027726366.
It is an arithmetic number, because the mean of its divisors is an integer number (2670027726366).
Almost surely, 25340055452731 is an apocalyptic number.
5340055452731 is a deficient number, since it is larger than the sum of its proper divisors (1).
5340055452731 is an equidigital number, since it uses as much as digits as its factorization.
5340055452731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260000, while the sum is 44.
The spelling of 5340055452731 in words is "five trillion, three hundred forty billion, fifty-five million, four hundred fifty-two thousand, seven hundred thirty-one".
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