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5340551150057 is a prime number
BaseRepresentation
bin100110110110111000110…
…1001110111100111101001
3200220112220012012000101212
41031231301221313213221
51144444422043300212
615205225413322505
71060561556530004
oct115556151674751
920815805160355
105340551150057
111779a07995012
1272304b936435
132c97c51c9206
141466ac36453b
1593dbee85e22
hex4db71a779e9

5340551150057 has 2 divisors, whose sum is σ = 5340551150058. Its totient is φ = 5340551150056.

The previous prime is 5340551150021. The next prime is 5340551150059. The reversal of 5340551150057 is 7500511550435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5340485280601 + 65869456 = 2310949^2 + 8116^2 .

It is a cyclic number.

It is not a de Polignac number, because 5340551150057 - 26 = 5340551149993 is a prime.

It is a super-2 number, since 2×53405511500572 (a number of 26 digits) contains 22 as substring.

Together with 5340551150059, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5340551149996 and 5340551150023.

It is not a weakly prime, because it can be changed into another prime (5340551150059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670275575028 + 2670275575029.

It is an arithmetic number, because the mean of its divisors is an integer number (2670275575029).

Almost surely, 25340551150057 is an apocalyptic number.

It is an amenable number.

5340551150057 is a deficient number, since it is larger than the sum of its proper divisors (1).

5340551150057 is an equidigital number, since it uses as much as digits as its factorization.

5340551150057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 262500, while the sum is 41.

The spelling of 5340551150057 in words is "five trillion, three hundred forty billion, five hundred fifty-one million, one hundred fifty thousand, fifty-seven".