Base | Representation |
---|---|
bin | 100110110111001010001… |
… | …1110111111010000110101 |
3 | 200220121101220202002021222 |
4 | 1031232110132333100311 |
5 | 1200002121142002331 |
6 | 15205403410120125 |
7 | 1060612213446104 |
oct | 115562436772065 |
9 | 20817356662258 |
10 | 5341135500341 |
11 | 177a187824033 |
12 | 723193580045 |
13 | 2c98892a5804 |
14 | 146725bd603b |
15 | 93e06411b7b |
hex | 4db947bf435 |
5341135500341 has 2 divisors, whose sum is σ = 5341135500342. Its totient is φ = 5341135500340.
The previous prime is 5341135500331. The next prime is 5341135500347. The reversal of 5341135500341 is 1430055311435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3348365661316 + 1992769839025 = 1829854^2 + 1411655^2 .
It is a cyclic number.
It is not a de Polignac number, because 5341135500341 - 222 = 5341131306037 is a prime.
It is a super-2 number, since 2×53411355003412 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5341135500347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670567750170 + 2670567750171.
It is an arithmetic number, because the mean of its divisors is an integer number (2670567750171).
Almost surely, 25341135500341 is an apocalyptic number.
It is an amenable number.
5341135500341 is a deficient number, since it is larger than the sum of its proper divisors (1).
5341135500341 is an equidigital number, since it uses as much as digits as its factorization.
5341135500341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 5341135500341 in words is "five trillion, three hundred forty-one billion, one hundred thirty-five million, five hundred thousand, three hundred forty-one".
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