Base | Representation |
---|---|
bin | 100110110111001010001… |
… | …1110111111110001010011 |
3 | 200220121101220202012010221 |
4 | 1031232110132333301103 |
5 | 1200002121142034134 |
6 | 15205403410133511 |
7 | 1060612213455133 |
oct | 115562436776123 |
9 | 20817356665127 |
10 | 5341135502419 |
11 | 177a187825652 |
12 | 723193581297 |
13 | 2c98892a6742 |
14 | 146725bd6ac3 |
15 | 93e064125b4 |
hex | 4db947bfc53 |
5341135502419 has 2 divisors, whose sum is σ = 5341135502420. Its totient is φ = 5341135502418.
The previous prime is 5341135502341. The next prime is 5341135502459. The reversal of 5341135502419 is 9142055311435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5341135502419 - 29 = 5341135501907 is a prime.
It is a super-2 number, since 2×53411355024192 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5341135502459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670567751209 + 2670567751210.
It is an arithmetic number, because the mean of its divisors is an integer number (2670567751210).
Almost surely, 25341135502419 is an apocalyptic number.
5341135502419 is a deficient number, since it is larger than the sum of its proper divisors (1).
5341135502419 is an equidigital number, since it uses as much as digits as its factorization.
5341135502419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 43.
The spelling of 5341135502419 in words is "five trillion, three hundred forty-one billion, one hundred thirty-five million, five hundred two thousand, four hundred nineteen".
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