53412511242133 has 2 divisors, whose sum is σ = 53412511242134. Its totient is φ = 53412511242132.

The previous prime is 53412511242049. The next prime is 53412511242143. The reversal of 53412511242133 is 33124211521435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38427390234289 + 14985121007844 = 6198983^2 + 3871062^2 .

It is a cyclic number.

It is not a de Polignac number, because 53412511242133 - 2¹³ = 53412511233941 is a prime.

It is a super-3 number, since 3×53412511242133³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 53412511242092 and 53412511242101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53412511242143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26706255621066 + 26706255621067.

It is an arithmetic number, because the mean of its divisors is an integer number (26706255621067).

Almost surely, 2^{53412511242133} is an apocalyptic number.

It is an amenable number.

53412511242133 is a deficient number, since it is larger than the sum of its proper divisors (1).

53412511242133 is an equidigital number, since it uses as much as digits as its factorization.

53412511242133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 86400, while the sum is 37.

Adding to 53412511242133 its reverse (33124211521435), we get a palindrome (86536722763568).

The spelling of 53412511242133 in words is "fifty-three trillion, four hundred twelve billion, five hundred eleven million, two hundred forty-two thousand, one hundred thirty-three".