Base | Representation |
---|---|
bin | 100110110111010011010… |
… | …1010001111101100100101 |
3 | 200220122012011112200102002 |
4 | 1031232212222033230211 |
5 | 1200003232223104000 |
6 | 15205453542055045 |
7 | 1060622605424225 |
oct | 115564652175445 |
9 | 20818164480362 |
10 | 5341440441125 |
11 | 177a323972608 |
12 | 72325971a485 |
13 | 2c9907513449 |
14 | 1467544d4085 |
15 | 93e230998d5 |
hex | 4dba6a8fb25 |
5341440441125 has 8 divisors (see below), whose sum is σ = 6666117670680. Its totient is φ = 4273152352800.
The previous prime is 5341440441121. The next prime is 5341440441131. The reversal of 5341440441125 is 5211440441435.
It can be written as a sum of positive squares in 4 ways, for example, as 430988311009 + 4910452130116 = 656497^2 + 2215954^2 .
It is not a de Polignac number, because 5341440441125 - 22 = 5341440441121 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5341440441121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21365761640 + ... + 21365761889.
It is an arithmetic number, because the mean of its divisors is an integer number (833264708835).
Almost surely, 25341440441125 is an apocalyptic number.
It is an amenable number.
5341440441125 is a deficient number, since it is larger than the sum of its proper divisors (1324677229555).
5341440441125 is an equidigital number, since it uses as much as digits as its factorization.
5341440441125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42731523544 (or 42731523534 counting only the distinct ones).
The product of its (nonzero) digits is 153600, while the sum is 38.
The spelling of 5341440441125 in words is "five trillion, three hundred forty-one billion, four hundred forty million, four hundred forty-one thousand, one hundred twenty-five".
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