Base | Representation |
---|---|
bin | 100110110111101100111… |
… | …1001010110010100101111 |
3 | 200220201102002000202020221 |
4 | 1031233121321112110233 |
5 | 1200012012302212242 |
6 | 15210115130152211 |
7 | 1060653114036661 |
oct | 115573171262457 |
9 | 20821362022227 |
10 | 5342300038447 |
11 | 177a725109819 |
12 | 723459582667 |
13 | 2c9a13631c08 |
14 | 1467d6734531 |
15 | 93e73795167 |
hex | 4dbd9e5652f |
5342300038447 has 2 divisors, whose sum is σ = 5342300038448. Its totient is φ = 5342300038446.
The previous prime is 5342300038421. The next prime is 5342300038457. The reversal of 5342300038447 is 7448300032435.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5342300038447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5342300038457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2671150019223 + 2671150019224.
It is an arithmetic number, because the mean of its divisors is an integer number (2671150019224).
Almost surely, 25342300038447 is an apocalyptic number.
5342300038447 is a deficient number, since it is larger than the sum of its proper divisors (1).
5342300038447 is an equidigital number, since it uses as much as digits as its factorization.
5342300038447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 967680, while the sum is 43.
The spelling of 5342300038447 in words is "five trillion, three hundred forty-two billion, three hundred million, thirty-eight thousand, four hundred forty-seven".
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