Base | Representation |
---|---|
bin | 111100101111001000010110… |
… | …0101010011101010011010011 |
3 | 2121001121010221002022001112012 |
4 | 1321132100230222131103103 |
5 | 1030011014423140424134 |
6 | 5132123524433453135 |
7 | 220346536035021605 |
oct | 17136205452352323 |
9 | 2531533832261465 |
10 | 534243141342419 |
11 | 145254275663793 |
12 | 4bb03a971111ab |
13 | 19c13bb1a41982 |
14 | 95cd7126b1175 |
15 | 41b6d542a16ce |
hex | 1e5e42ca9d4d3 |
534243141342419 has 2 divisors, whose sum is σ = 534243141342420. Its totient is φ = 534243141342418.
The previous prime is 534243141342359. The next prime is 534243141342473. The reversal of 534243141342419 is 914243141342435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 534243141342419 - 212 = 534243141338323 is a prime.
It is a super-3 number, since 3×5342431413424193 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (534243141342499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267121570671209 + 267121570671210.
It is an arithmetic number, because the mean of its divisors is an integer number (267121570671210).
Almost surely, 2534243141342419 is an apocalyptic number.
534243141342419 is a deficient number, since it is larger than the sum of its proper divisors (1).
534243141342419 is an equidigital number, since it uses as much as digits as its factorization.
534243141342419 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4976640, while the sum is 50.
The spelling of 534243141342419 in words is "five hundred thirty-four trillion, two hundred forty-three billion, one hundred forty-one million, three hundred forty-two thousand, four hundred nineteen".
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