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534243141342473 is a prime number
BaseRepresentation
bin111100101111001000010110…
…0101010011101010100001001
32121001121010221002022001121012
41321132100230222131110021
51030011014423140424343
65132123524433453305
7220346536035022013
oct17136205452352411
92531533832261535
10534243141342473
11145254275663832
124bb03a97111235
1319c13bb1a419c4
1495cd7126b11b3
1541b6d542a1718
hex1e5e42ca9d509

534243141342473 has 2 divisors, whose sum is σ = 534243141342474. Its totient is φ = 534243141342472.

The previous prime is 534243141342419. The next prime is 534243141342499. The reversal of 534243141342473 is 374243141342435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 486424436521024 + 47818704821449 = 22055032^2 + 6915107^2 .

It is a cyclic number.

It is not a de Polignac number, because 534243141342473 - 224 = 534243124565257 is a prime.

It is a super-3 number, since 3×5342431413424733 (a number of 45 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (534243141342773) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267121570671236 + 267121570671237.

It is an arithmetic number, because the mean of its divisors is an integer number (267121570671237).

Almost surely, 2534243141342473 is an apocalyptic number.

It is an amenable number.

534243141342473 is a deficient number, since it is larger than the sum of its proper divisors (1).

534243141342473 is an equidigital number, since it uses as much as digits as its factorization.

534243141342473 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11612160, while the sum is 50.

The spelling of 534243141342473 in words is "five hundred thirty-four trillion, two hundred forty-three billion, one hundred forty-one million, three hundred forty-two thousand, four hundred seventy-three".