Base | Representation |
---|---|
bin | 100110110111110101111… |
… | …1110100101011111110111 |
3 | 200220202012012212011201201 |
4 | 1031233223332211133313 |
5 | 1200013122432314312 |
6 | 15210205204233331 |
7 | 1060663456423342 |
oct | 115575376453767 |
9 | 20822165764651 |
10 | 5342603401207 |
11 | 177a87037a746 |
12 | 72352309b847 |
13 | 2c9a614394c7 |
14 | 146824b41459 |
15 | 93e9021a557 |
hex | 4dbebfa57f7 |
5342603401207 has 2 divisors, whose sum is σ = 5342603401208. Its totient is φ = 5342603401206.
The previous prime is 5342603401199. The next prime is 5342603401217. The reversal of 5342603401207 is 7021043062435.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5342603401207 - 23 = 5342603401199 is a prime.
It is a super-2 number, since 2×53426034012072 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5342603401217) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2671301700603 + 2671301700604.
It is an arithmetic number, because the mean of its divisors is an integer number (2671301700604).
Almost surely, 25342603401207 is an apocalyptic number.
5342603401207 is a deficient number, since it is larger than the sum of its proper divisors (1).
5342603401207 is an equidigital number, since it uses as much as digits as its factorization.
5342603401207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 37.
The spelling of 5342603401207 in words is "five trillion, three hundred forty-two billion, six hundred three million, four hundred one thousand, two hundred seven".
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