Base | Representation |
---|---|
bin | 1111100011001111011… |
… | …00000100101001000100 |
3 | 1220002011100222100001222 |
4 | 13301213230010221010 |
5 | 32223234240120200 |
6 | 1045243340335512 |
7 | 53413560151406 |
oct | 7614754045104 |
9 | 1802140870058 |
10 | 534315551300 |
11 | 196669221053 |
12 | 87679244598 |
13 | 3b50261890b |
14 | 1bc0a882b76 |
15 | dd73563d85 |
hex | 7c67b04a44 |
534315551300 has 36 divisors (see below), whose sum is σ = 1159498026960. Its totient is φ = 213720085920.
The previous prime is 534315551293. The next prime is 534315551309. The reversal of 534315551300 is 3155513435.
It is a super-2 number, since 2×5343155513002 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (534315551309) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5300771 + ... + 5400629.
Almost surely, 2534315551300 is an apocalyptic number.
534315551300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
534315551300 is an abundant number, since it is smaller than the sum of its proper divisors (625182475660).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
534315551300 is a wasteful number, since it uses less digits than its factorization.
534315551300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153380 (or 153373 counting only the distinct ones).
The product of its (nonzero) digits is 67500, while the sum is 35.
The spelling of 534315551300 in words is "five hundred thirty-four billion, three hundred fifteen million, five hundred fifty-one thousand, three hundred".
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