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534335104325689 is a prime number
BaseRepresentation
bin111100101111110011001011…
…0000101011001100000111001
32121001220221022010212122110121
41321133212112011121200321
51030014021243201410224
65132234054055413241
7220356303001335502
oct17137462605314071
92531827263778417
10534335104325689
1114528a2773391a7
124bb19881384221
1319c1c77944a5c4
1495d3d5818dba9
1541b9437b2cbe4
hex1e5f996159839

534335104325689 has 2 divisors, whose sum is σ = 534335104325690. Its totient is φ = 534335104325688.

The previous prime is 534335104325669. The next prime is 534335104325717. The reversal of 534335104325689 is 986523401533435.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 529156043505664 + 5179060820025 = 23003392^2 + 2275755^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-534335104325689 is a prime.

It is not a weakly prime, because it can be changed into another prime (534335104325669) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267167552162844 + 267167552162845.

It is an arithmetic number, because the mean of its divisors is an integer number (267167552162845).

Almost surely, 2534335104325689 is an apocalyptic number.

It is an amenable number.

534335104325689 is a deficient number, since it is larger than the sum of its proper divisors (1).

534335104325689 is an equidigital number, since it uses as much as digits as its factorization.

534335104325689 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 139968000, while the sum is 61.

The spelling of 534335104325689 in words is "five hundred thirty-four trillion, three hundred thirty-five billion, one hundred four million, three hundred twenty-five thousand, six hundred eighty-nine".