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534338096263 is a prime number
BaseRepresentation
bin1111100011010010000…
…10000100110010000111
31220002012221101201221121
413301221002010302013
532223311023040023
61045245503454411
753414252610226
oct7615102046207
91802187351847
10534338096263
1119667aa1a454
12876848b7407
133b5071b052a
141bc0d870cbd
15dd75518d5d
hex7c69084c87

534338096263 has 2 divisors, whose sum is σ = 534338096264. Its totient is φ = 534338096262.

The previous prime is 534338096251. The next prime is 534338096267. The reversal of 534338096263 is 362690833435.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 534338096263 - 29 = 534338095751 is a prime.

It is a super-2 number, since 2×5343380962632 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 534338096263.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (534338096267) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267169048131 + 267169048132.

It is an arithmetic number, because the mean of its divisors is an integer number (267169048132).

Almost surely, 2534338096263 is an apocalyptic number.

534338096263 is a deficient number, since it is larger than the sum of its proper divisors (1).

534338096263 is an equidigital number, since it uses as much as digits as its factorization.

534338096263 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8398080, while the sum is 52.

The spelling of 534338096263 in words is "five hundred thirty-four billion, three hundred thirty-eight million, ninety-six thousand, two hundred sixty-three".