Base | Representation |
---|---|
bin | 11000010011001001100000… |
… | …11001111100000001010111 |
3 | 21000012021210012021110022021 |
4 | 30021210300121330001113 |
5 | 24000432324030012401 |
6 | 305351245344514011 |
7 | 14153341504635604 |
oct | 1411446031740127 |
9 | 230167705243267 |
10 | 53434500235351 |
11 | 16031498391664 |
12 | 5babb6a01b907 |
13 | 23a7b0c3b2c51 |
14 | d2a35a6796ab |
15 | 629e49a0e2a1 |
hex | 30993067c057 |
53434500235351 has 2 divisors, whose sum is σ = 53434500235352. Its totient is φ = 53434500235350.
The previous prime is 53434500235313. The next prime is 53434500235373. The reversal of 53434500235351 is 15353200543435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53434500235351 - 239 = 52884744421463 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53434500235298 and 53434500235307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53434500335351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26717250117675 + 26717250117676.
It is an arithmetic number, because the mean of its divisors is an integer number (26717250117676).
Almost surely, 253434500235351 is an apocalyptic number.
53434500235351 is a deficient number, since it is larger than the sum of its proper divisors (1).
53434500235351 is an equidigital number, since it uses as much as digits as its factorization.
53434500235351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620000, while the sum is 43.
Adding to 53434500235351 its reverse (15353200543435), we get a palindrome (68787700778786).
The spelling of 53434500235351 in words is "fifty-three trillion, four hundred thirty-four billion, five hundred million, two hundred thirty-five thousand, three hundred fifty-one".
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