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53434543531541 is a prime number
BaseRepresentation
bin11000010011001001100101…
…11111000110011000010101
321000012021220012202010111212
430021210302333012120111
524000432421121002131
6305351253532511205
714153342541642554
oct1411446277063025
9230167805663455
1053434543531541
111603150a873737
125babb8061b505
1323a7b18361bb3
14d2a362309d9b
15629e4d712a2b
hex309932fc6615

53434543531541 has 2 divisors, whose sum is σ = 53434543531542. Its totient is φ = 53434543531540.

The previous prime is 53434543531519. The next prime is 53434543531559. The reversal of 53434543531541 is 14513534543435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37664352362641 + 15770191168900 = 6137129^2 + 3971170^2 .

It is a cyclic number.

It is not a de Polignac number, because 53434543531541 - 26 = 53434543531477 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53434543531541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53434543531441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26717271765770 + 26717271765771.

It is an arithmetic number, because the mean of its divisors is an integer number (26717271765771).

Almost surely, 253434543531541 is an apocalyptic number.

It is an amenable number.

53434543531541 is a deficient number, since it is larger than the sum of its proper divisors (1).

53434543531541 is an equidigital number, since it uses as much as digits as its factorization.

53434543531541 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12960000, while the sum is 50.

The spelling of 53434543531541 in words is "fifty-three trillion, four hundred thirty-four billion, five hundred forty-three million, five hundred thirty-one thousand, five hundred forty-one".