Base | Representation |
---|---|
bin | 11000010011001010101110… |
… | …01100110101111110000010 |
3 | 21000012100110120000112010010 |
4 | 30021211113030311332002 |
5 | 24000440142141122424 |
6 | 305351434115245350 |
7 | 14153363600212410 |
oct | 1411452714657602 |
9 | 230170416015103 |
10 | 53435151114114 |
11 | 160317a18304a0 |
12 | 5bb010bba9856 |
13 | 23a7bb41b3c03 |
14 | d2a3bcca82b0 |
15 | 629e86c2c229 |
hex | 309957335f82 |
53435151114114 has 64 divisors (see below), whose sum is σ = 133263180536832. Its totient is φ = 13876938753600.
The previous prime is 53435151114109. The next prime is 53435151114161. The reversal of 53435151114114 is 41141115153435.
53435151114114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6905772 + ... + 12432215.
It is an arithmetic number, because the mean of its divisors is an integer number (2082237195888).
Almost surely, 253435151114114 is an apocalyptic number.
53435151114114 is an abundant number, since it is smaller than the sum of its proper divisors (79828029422718).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53435151114114 is a wasteful number, since it uses less digits than its factorization.
53435151114114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19343991.
The product of its digits is 72000, while the sum is 39.
Adding to 53435151114114 its reverse (41141115153435), we get a palindrome (94576266267549).
The spelling of 53435151114114 in words is "fifty-three trillion, four hundred thirty-five billion, one hundred fifty-one million, one hundred fourteen thousand, one hundred fourteen".
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