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534354120544 = 2516698566267
BaseRepresentation
bin1111100011010011111…
…11001100111101100000
31220002021001112212010111
413301221333030331200
532223324123324134
61045251235141104
753414536040236
oct7615177147540
91802231485114
10534354120544
11196688a74762
128768a144794
133b50a60115a
141bc11a42956
15dd76b31c64
hex7c69fccf60

534354120544 has 12 divisors (see below), whose sum is σ = 1052009674884. Its totient is φ = 267177060256.

The previous prime is 534354120533. The next prime is 534354120569. The reversal of 534354120544 is 445021453435.

It is a super-3 number, since 3×5343541205443 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 534354120497 and 534354120506.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8349283102 + ... + 8349283165.

It is an arithmetic number, because the mean of its divisors is an integer number (87667472907).

Almost surely, 2534354120544 is an apocalyptic number.

It is an amenable number.

534354120544 is a deficient number, since it is larger than the sum of its proper divisors (517655554340).

534354120544 is a wasteful number, since it uses less digits than its factorization.

534354120544 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16698566277 (or 16698566269 counting only the distinct ones).

The product of its (nonzero) digits is 576000, while the sum is 40.

Adding to 534354120544 its reverse (445021453435), we get a palindrome (979375573979).

The spelling of 534354120544 in words is "five hundred thirty-four billion, three hundred fifty-four million, one hundred twenty thousand, five hundred forty-four".

Divisors: 1 2 4 8 16 32 16698566267 33397132534 66794265068 133588530136 267177060272 534354120544