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5344013 is a prime number
BaseRepresentation
bin10100011000101100001101
3101001111121102
4110120230031
52332002023
6310312445
763265133
oct24305415
911044542
105344013
113020044
121958725
13115154c
149d1753
15708628
hex518b0d

5344013 has 2 divisors, whose sum is σ = 5344014. Its totient is φ = 5344012.

The previous prime is 5344007. The next prime is 5344037. The reversal of 5344013 is 3104435.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3232804 + 2111209 = 1798^2 + 1453^2 .

It is a cyclic number.

It is not a de Polignac number, because 5344013 - 28 = 5343757 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5344813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2672006 + 2672007.

It is an arithmetic number, because the mean of its divisors is an integer number (2672007).

Almost surely, 25344013 is an apocalyptic number.

It is an amenable number.

5344013 is a deficient number, since it is larger than the sum of its proper divisors (1).

5344013 is an equidigital number, since it uses as much as digits as its factorization.

5344013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 20.

The square root of 5344013 is about 2311.7121360585. The cubic root of 5344013 is about 174.8326345449.

Adding to 5344013 its reverse (3104435), we get a palindrome (8448448).

The spelling of 5344013 in words is "five million, three hundred forty-four thousand, thirteen".