Base | Representation |
---|---|
bin | 110001110001101000… |
… | …011011101001111001 |
3 | 12002221202010201211102 |
4 | 301301220123221321 |
5 | 1333424141010433 |
6 | 40315221541145 |
7 | 3601304530154 |
oct | 616150335171 |
9 | 162852121742 |
10 | 53446031993 |
11 | 20736989982 |
12 | a436b747b5 |
13 | 5069991b03 |
14 | 2830280c9b |
15 | 15cc1914e8 |
hex | c71a1ba79 |
53446031993 has 2 divisors, whose sum is σ = 53446031994. Its totient is φ = 53446031992.
The previous prime is 53446031981. The next prime is 53446032001. The reversal of 53446031993 is 39913064435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52172041744 + 1273990249 = 228412^2 + 35693^2 .
It is a cyclic number.
It is not a de Polignac number, because 53446031993 - 210 = 53446030969 is a prime.
It is not a weakly prime, because it can be changed into another prime (53446031693) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26723015996 + 26723015997.
It is an arithmetic number, because the mean of its divisors is an integer number (26723015997).
Almost surely, 253446031993 is an apocalyptic number.
It is an amenable number.
53446031993 is a deficient number, since it is larger than the sum of its proper divisors (1).
53446031993 is an equidigital number, since it uses as much as digits as its factorization.
53446031993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1049760, while the sum is 47.
The spelling of 53446031993 in words is "fifty-three billion, four hundred forty-six million, thirty-one thousand, nine hundred ninety-three".
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