Base | Representation |
---|---|
bin | 110001110011000100… |
… | …110101001001001111 |
3 | 12010000102201022200201 |
4 | 301303010311021033 |
5 | 1334001341104042 |
6 | 40321445034331 |
7 | 3602020441216 |
oct | 616304651117 |
9 | 163012638621 |
10 | 53470253647 |
11 | 20749622a78 |
12 | a4430b59a7 |
13 | 50719c2955 |
14 | 283358807d |
15 | 15ce3781b7 |
hex | c7313524f |
53470253647 has 2 divisors, whose sum is σ = 53470253648. Its totient is φ = 53470253646.
The previous prime is 53470253633. The next prime is 53470253659. The reversal of 53470253647 is 74635207435.
53470253647 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53470253647 - 215 = 53470220879 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53470253597 and 53470253606.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53470253747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26735126823 + 26735126824.
It is an arithmetic number, because the mean of its divisors is an integer number (26735126824).
Almost surely, 253470253647 is an apocalyptic number.
53470253647 is a deficient number, since it is larger than the sum of its proper divisors (1).
53470253647 is an equidigital number, since it uses as much as digits as its factorization.
53470253647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2116800, while the sum is 46.
The spelling of 53470253647 in words is "fifty-three billion, four hundred seventy million, two hundred fifty-three thousand, six hundred forty-seven".
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