Base | Representation |
---|---|
bin | 110001110011010100… |
… | …110101000001111011 |
3 | 12010000201121101112222 |
4 | 301303110311001323 |
5 | 1334003424304413 |
6 | 40322114554255 |
7 | 3602101206152 |
oct | 616324650173 |
9 | 163021541488 |
10 | 53474447483 |
11 | 20750a27956 |
12 | a44459898b |
13 | 5072830802 |
14 | 2833d5a599 |
15 | 15ce905b08 |
hex | c7353507b |
53474447483 has 2 divisors, whose sum is σ = 53474447484. Its totient is φ = 53474447482.
The previous prime is 53474447399. The next prime is 53474447489. The reversal of 53474447483 is 38474447435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53474447483 - 28 = 53474447227 is a prime.
It is a super-2 number, since 2×534744474832 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53474447489) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26737223741 + 26737223742.
It is an arithmetic number, because the mean of its divisors is an integer number (26737223742).
Almost surely, 253474447483 is an apocalyptic number.
53474447483 is a deficient number, since it is larger than the sum of its proper divisors (1).
53474447483 is an equidigital number, since it uses as much as digits as its factorization.
53474447483 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18063360, while the sum is 53.
The spelling of 53474447483 in words is "fifty-three billion, four hundred seventy-four million, four hundred forty-seven thousand, four hundred eighty-three".
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