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5349742479373 is a prime number
BaseRepresentation
bin100110111011001010110…
…0000000000100000001101
3200221102121202021220220011
41031312111200000200031
51200122233033314443
615213345431353221
71061335414533325
oct115662540004015
920842552256804
105349742479373
1117828a4186846
12724995b22811
132ca62b4b9006
14146d00d42285
159425bd57b9d
hex4dd9580080d

5349742479373 has 2 divisors, whose sum is σ = 5349742479374. Its totient is φ = 5349742479372.

The previous prime is 5349742479353. The next prime is 5349742479469. The reversal of 5349742479373 is 3739742479435.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4218661307844 + 1131081171529 = 2053938^2 + 1063523^2 .

It is a cyclic number.

It is not a de Polignac number, because 5349742479373 - 221 = 5349740382221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5349742479299 and 5349742479308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5349742479353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2674871239686 + 2674871239687.

It is an arithmetic number, because the mean of its divisors is an integer number (2674871239687).

Almost surely, 25349742479373 is an apocalyptic number.

It is an amenable number.

5349742479373 is a deficient number, since it is larger than the sum of its proper divisors (1).

5349742479373 is an equidigital number, since it uses as much as digits as its factorization.

5349742479373 is an evil number, because the sum of its binary digits is even.

The product of its digits is 480090240, while the sum is 67.

The spelling of 5349742479373 in words is "five trillion, three hundred forty-nine billion, seven hundred forty-two million, four hundred seventy-nine thousand, three hundred seventy-three".