Base | Representation |
---|---|
bin | 100110111011010101110… |
… | …0010001101001000010011 |
3 | 200221110120111220100022212 |
4 | 1031312223202031020103 |
5 | 1200124012202413011 |
6 | 15213450235022335 |
7 | 1061350523653313 |
oct | 115665342151023 |
9 | 20843514810285 |
10 | 5350112154131 |
11 | 1782a73919978 |
12 | 724a7989a9ab |
13 | 2ca689c70584 |
14 | 146d38091443 |
15 | 9427e52b08b |
hex | 4ddab88d213 |
5350112154131 has 2 divisors, whose sum is σ = 5350112154132. Its totient is φ = 5350112154130.
The previous prime is 5350112154097. The next prime is 5350112154173. The reversal of 5350112154131 is 1314512110535.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5350112154131 - 210 = 5350112153107 is a prime.
It is a super-2 number, since 2×53501121541312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5350112114131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2675056077065 + 2675056077066.
It is an arithmetic number, because the mean of its divisors is an integer number (2675056077066).
Almost surely, 25350112154131 is an apocalyptic number.
5350112154131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5350112154131 is an equidigital number, since it uses as much as digits as its factorization.
5350112154131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9000, while the sum is 32.
Adding to 5350112154131 its reverse (1314512110535), we get a palindrome (6664624264666).
The spelling of 5350112154131 in words is "five trillion, three hundred fifty billion, one hundred twelve million, one hundred fifty-four thousand, one hundred thirty-one".
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