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5350191047 is a prime number
BaseRepresentation
bin1001111101110010…
…10110111111000111
3111210212022212100222
410332321112333013
541424122103142
62242521054555
7246403605425
oct47671267707
914725285328
105350191047
1122a60527a3
12105392745b
13673580a26
1438a7bc115
15214a7bbd2
hex13ee56fc7

5350191047 has 2 divisors, whose sum is σ = 5350191048. Its totient is φ = 5350191046.

The previous prime is 5350190987. The next prime is 5350191059. The reversal of 5350191047 is 7401910535.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5350191047 - 212 = 5350186951 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5350190998 and 5350191016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5350191547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2675095523 + 2675095524.

It is an arithmetic number, because the mean of its divisors is an integer number (2675095524).

Almost surely, 25350191047 is an apocalyptic number.

5350191047 is a deficient number, since it is larger than the sum of its proper divisors (1).

5350191047 is an equidigital number, since it uses as much as digits as its factorization.

5350191047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18900, while the sum is 35.

The square root of 5350191047 is about 73145.0001503862. Note that the first 3 decimals coincide. The cubic root of 5350191047 is about 1748.9998145364. Note that the first 3 decimals are identical.

The spelling of 5350191047 in words is "five billion, three hundred fifty million, one hundred ninety-one thousand, forty-seven".