Base | Representation |
---|---|
bin | 11000010101001011111111… |
… | …11100110011111110000011 |
3 | 21000102222121101021100010101 |
4 | 30022211333330303332003 |
5 | 24003104311342113321 |
6 | 305443353005343231 |
7 | 14161401506161624 |
oct | 1412457774637603 |
9 | 230388541240111 |
10 | 53504554254211 |
11 | 16059177019915 |
12 | 600165ab67b17 |
13 | 23b15c4a92008 |
14 | d2d8c4513a4b |
15 | 62bb99c40791 |
hex | 30a97ff33f83 |
53504554254211 has 2 divisors, whose sum is σ = 53504554254212. Its totient is φ = 53504554254210.
The previous prime is 53504554254199. The next prime is 53504554254227. The reversal of 53504554254211 is 11245245540535.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53504554254211 - 213 = 53504554246019 is a prime.
It is a super-3 number, since 3×535045542542113 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (53504554254251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26752277127105 + 26752277127106.
It is an arithmetic number, because the mean of its divisors is an integer number (26752277127106).
Almost surely, 253504554254211 is an apocalyptic number.
53504554254211 is a deficient number, since it is larger than the sum of its proper divisors (1).
53504554254211 is an equidigital number, since it uses as much as digits as its factorization.
53504554254211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400000, while the sum is 46.
Adding to 53504554254211 its reverse (11245245540535), we get a palindrome (64749799794746).
The spelling of 53504554254211 in words is "fifty-three trillion, five hundred four billion, five hundred fifty-four million, two hundred fifty-four thousand, two hundred eleven".
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