Base | Representation |
---|---|
bin | 100110111011100001011… |
… | …0111001110100100001011 |
3 | 200221111120210100212011221 |
4 | 1031313002313032210023 |
5 | 1200130312401303003 |
6 | 15213553135502511 |
7 | 1061363315463025 |
oct | 115670267164413 |
9 | 20844523325157 |
10 | 5350503541003 |
11 | 17831548416a5 |
12 | 724b68987a37 |
13 | 2ca72008763a |
14 | 146d74053015 |
15 | 942a3a8c7bd |
hex | 4ddc2dce90b |
5350503541003 has 2 divisors, whose sum is σ = 5350503541004. Its totient is φ = 5350503541002.
The previous prime is 5350503540959. The next prime is 5350503541027. The reversal of 5350503541003 is 3001453050535.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5350503541003 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5350503541003.
It is not a weakly prime, because it can be changed into another prime (5350503548003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2675251770501 + 2675251770502.
It is an arithmetic number, because the mean of its divisors is an integer number (2675251770502).
Almost surely, 25350503541003 is an apocalyptic number.
5350503541003 is a deficient number, since it is larger than the sum of its proper divisors (1).
5350503541003 is an equidigital number, since it uses as much as digits as its factorization.
5350503541003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67500, while the sum is 34.
Adding to 5350503541003 its reverse (3001453050535), we get a palindrome (8351956591538).
The spelling of 5350503541003 in words is "five trillion, three hundred fifty billion, five hundred three million, five hundred forty-one thousand, three".
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