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53511814255117 is a prime number
BaseRepresentation
bin11000010101011001100001…
…01011100001001000001101
321000110200100100020121002211
430022230300223201020031
524003214143422130432
6305450553232350421
714162046433155211
oct1412546053411015
9230420310217084
1053511814255117
1116061262107a69
126002b463a5411
1323b21b0bcc73a
14d2ddb27d0941
1562be722b6d47
hex30ab30ae120d

53511814255117 has 2 divisors, whose sum is σ = 53511814255118. Its totient is φ = 53511814255116.

The previous prime is 53511814255013. The next prime is 53511814255139. The reversal of 53511814255117 is 71155241811535.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27625840848841 + 25885973406276 = 5256029^2 + 5087826^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53511814255117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53511814255157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26755907127558 + 26755907127559.

It is an arithmetic number, because the mean of its divisors is an integer number (26755907127559).

Almost surely, 253511814255117 is an apocalyptic number.

It is an amenable number.

53511814255117 is a deficient number, since it is larger than the sum of its proper divisors (1).

53511814255117 is an equidigital number, since it uses as much as digits as its factorization.

53511814255117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 840000, while the sum is 49.

The spelling of 53511814255117 in words is "fifty-three trillion, five hundred eleven billion, eight hundred fourteen million, two hundred fifty-five thousand, one hundred seventeen".