Base | Representation |
---|---|
bin | 100110111101010011111… |
… | …0010111100100010011111 |
3 | 200221212111110121202122221 |
4 | 1031322213302330202133 |
5 | 1200211144131313210 |
6 | 15215430222450211 |
7 | 1061560434321526 |
oct | 115724762744237 |
9 | 20855443552587 |
10 | 5354344401055 |
11 | 1784845910701 |
12 | 72585b133967 |
13 | 2cabb2a29bb0 |
14 | 14721a1bd4bd |
15 | 9442ad7a1da |
hex | 4dea7cbc89f |
5354344401055 has 32 divisors (see below), whose sum is σ = 6991634377728. Its totient is φ = 3912744960000.
The previous prime is 5354344401047. The next prime is 5354344401101. The reversal of 5354344401055 is 5501044434535.
5354344401055 = T523986 + T523987 + ... + T524024.
It is not a de Polignac number, because 5354344401055 - 23 = 5354344401047 is a prime.
It is a super-2 number, since 2×53543444010552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 57650655 + ... + 57743455.
It is an arithmetic number, because the mean of its divisors is an integer number (218488574304).
Almost surely, 25354344401055 is an apocalyptic number.
5354344401055 is a deficient number, since it is larger than the sum of its proper divisors (1637289976673).
5354344401055 is a wasteful number, since it uses less digits than its factorization.
5354344401055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102067.
The product of its (nonzero) digits is 1440000, while the sum is 43.
The spelling of 5354344401055 in words is "five trillion, three hundred fifty-four billion, three hundred forty-four million, four hundred one thousand, fifty-five".
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